Hello,
I often have varied groupings under one beam and have used the solution
given by Michael Werner. However, I have also created the following to
simplify entering the commands and the look of the score file:
bcLnone = \set stemLeftBeamCount = #0
bcRone = \set stemRightBeamCount = #1
bcLone = \set stemLeftBeamCount = #1
bcRtwo = \set stemRightBeamCount = #2
bcLtwo = \set stemLeftBeamCount = #2
Such as in:
\times 2/3 {f'16([ b, \bcRone f' ~} \bcLone f16 b,] ~ b16[ \bcRone f' ~
\bcLone f32-- b,16.] f'32[ b, ~ b8 f'16] ~ \times 4/6 {f16 b, \bcRone f'
~ \bcLone f b, f'] ~} | \times 2/3 {f16[ b, \bcRone f' ~} \bcLone f32 b,
f' b,] f'32[ b,32 ~ b8]) r16 fis'32([ b, ~ b8 fis'16] ~ \times 4/6 {
fis16[ b, \bcRone fis' ~ \bcLone fis b, fis'])} |
beam count example
Archer
On 14/12/2022 16:24, Michael Werner wrote:
Resending to include the list ... oops.
Something like this, perhaps?
\version "2.23.82"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'16[( aes \set stemRightBeamCount = #1 g) } \set
stemLeftBeamCount = #1 fis g] a8 b |
}
On Wed, Dec 14, 2022 at 10:42 AM Volodymyr Prokopyuk
<volodymyrprokop...@gmail.com> wrote:
Hello,
*Problem*
How can I separate a \tuplet from two sixteenths using a common
eightingth beam?
*Example code*
\version "2.23.81"
\relative {
\clef treble
\key c \minor
\time 2/4
\tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}
image.png
*Desired result*
image.png
I've tried to adjust the baseMoment, beatStructure, subdivideBeats
and strictBeatBeaming but without success.
Thank you very much,
Vlad
\version "2.22.1"
% beamcountexample.ly
%Shorthand for setting the beam count:
bcLnone = \set stemLeftBeamCount = #0
bcRone = \set stemRightBeamCount = #1
bcLone = \set stemLeftBeamCount = #1
bcRtwo = \set stemRightBeamCount = #2
bcLtwo = \set stemLeftBeamCount = #2
\score {
\new Staff {
\relative c {
\clef "treble_8"
\time 4/4
\override TupletBracket.bracket-visibility = ##t
\times 2/3 {f'16([ b, \bcRone f' ~} \bcLone f16 b,] ~ b16[ \bcRone f' ~ \bcLone f32-- b,16.] f'32[ b, ~ b8 f'16] ~ \times 4/6 {f16 b, \bcRone f' ~ \bcLone f b, f'] ~} | \times 2/3 {f16[ b, \bcRone f' ~} \bcLone f32 b, f' b,] f'32[ b,32 ~ b8]) r16 fis'32([ b, ~ b8 fis'16] ~ \times 4/6 { fis16[ b, \bcRone fis' ~ \bcLone fis b, fis'])} |
}
}
}