Thank you, Aaron - very nice of you. In fact, there is no need for the microscopic precision of that chain element - the approximate look is enough to completely satisfy me. The different task is to build a wavy line of the same proportions like these lines attached to my letter.
*Леонід - Leonid* <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail&utm_term=icon> Virus-free. www.avast.com <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail&utm_term=link> <#m_6332395341811365710_DAB4FAD8-2DD7-40BB-A1B8-4E2AA1F9FDF2> On Thu, Nov 25, 2021 at 1:19 PM Aaron Hill <lilyp...@hillvisions.com> wrote: > On 2021-11-25 6:22 am, Leonid Hrabovsky wrote: > > Hello Jean, > > after receiving your code, I started tweaking its numbers with the aim > > to > > obtain the lines of the proper size - and now I have approximately two > > of > > three I need - one built out of arches and one angulary. I am going to > > try > > to maybe tweak the height a bit more in order to make the arch similar > > to a > > semicircle (arch-length 4, arch-height 2?) as an extra variant. This is > > the > > final code of these: > > A cubic Bézier curve can reasonably approximate a quarter circle. > > Therefore, to get a semicircle, you will need at least two segments: > > %%%% > \markup \path #0.2 > #'((moveto 0 0) > (curveto 0 1.1 0.9 2 2 2) > (curveto 3.1 2 4 1.1 4 0)) > %%%% > > Those control points are selected so that the midpoint (t=0.5) of the > curve is tangent to the circle. The exact value of (4/3)*(sqrt(2)-1) > was approximated as 0.55 in the above example. > > > -- Aaron Hill > <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail&utm_term=icon> Virus-free. www.avast.com <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail&utm_term=link> <#DAB4FAD8-2DD7-40BB-A1B8-4E2AA1F9FDF2>
