On Sat, 13 Apr 2019 at 11:41, Thomas Morley <thomasmorle...@gmail.com>
wrote:
> Am Sa., 13. Apr. 2019 um 11:16 Uhr schrieb Gianmaria Lari
> <gianmarial...@gmail.com>:
> >
> > I don't understand the following behaviour:
> >
> > \version "2.18.2"
> > \tagGroup #'(testOne testTwo)
> >
> > music = {
> > \tag #'testOne b
> > \tag #'testTwo b^"M "
> > }
> >
> > \keepWithTag #'testOne {\music~\music}
> > \keepWithTag #'testTwo {\music~\music}
> >
> > I would expect this would generate two pretty similar scores: the first
> >
> > b~b
> >
> > and the second
> >
> > b^M~b^M
> >
> > (so both with a tie)
> >
> > but instead it generates:
> >
> > b b (no tie!!)
> >
> > and
> >
> > b^M~b^M
> >
> > Where is the error?
> >
> > * *
> >
> > I noticed that if i invert the tag order
> >
> > music = {
> > \tag #'testTwo b^"M"
> > \tag #'testOne b
> > }
> >
> >
> > now the output is:
> >
> > b~b
> >
> > and
> >
> > b^M b^M (no tie!)
> >
> >
> > Any help?
> > Thank you, g.
>
> Hi Gianmaria,
>
> this is surely not 2.18.2-code ;)
>
:))))))
Well, I installed 2.21 but the reason is "signed" 2.18 it's because I
started from some old code and didn't pay attention to it!
> With 2.21.0 the construct
> \music ~ \music
> will add the Tie to the last event of first \music, if suitable. But
> this last element is removed by \keepWithTag #'testOne, thus no Tie.
>
Ok! Clear
The following would work, although I guess it's not what you want:
>
> { \keepWithTag #'testOne \music ~ \keepWithTag #'testOne \music }
>
You're right, this does not work for what I need :(
I probably could use a scheme substitution function (probably this is not
the correct name) but probably this would change to much my original code.
I have to think about it.
Thanks a lot Harm.
Ciao, g.
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