On Tue, 9 Apr 2019 at 17:07, David Kastrup <d...@gnu.org> wrote: > Gianmaria Lari <gianmarial...@gmail.com> writes: > > > On Tue, 9 Apr 2019 at 11:13, David Kastrup <d...@gnu.org> wrote: > > > >> Gianmaria Lari <gianmarial...@gmail.com> writes: > >> > >> > On Tue, 9 Apr 2019 at 10:45, David Kastrup <d...@gnu.org> wrote: > >> > > >> >> Gianmaria Lari <gianmarial...@gmail.com> writes: > >> >> > >> >> > Suppose I write > >> >> > > >> >> > > >> >> > #(define x '(1 2 3)) > >> >> > > >> >> > > >> >> > is there any way in scheme to print the memory address where x is > >> >> pointing > >> >> > to? (where is allocated the first element of the list) > >> >> > >> >> What do you need it for? If it is for identification, (hashq x > >> >> 1000000000) should usually do a reasonably good job. > >> >> > >> > > >> > I tried, it looks working. (Yes, it's for identification) > >> > > >> > And is there any way to print the memory address of x? (If I remember > >> > correctly was something like &x in c++). > >> > >> object-address maybe. But it's not like you can use it for anything. > > > > > > If I didn't make any mistakes, this code print the "address" of the first > > element of the list x and the "address" of the first element pointed by > the > > parameter "lst" of the "foo" function. > > This is Scheme, not C. 1 would not have an address anyway since it is > an immediate value (self-represented). And you are not printing the > address of the first element of the list but you are printing the > address of its cons cell. > [...]
Thank you David and Andrew for your extended reply and your suggestions! g.
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