Thanks, Aaron! Following your notes, I corrected the path to:
\path #0.3 #`((moveto ,xoff ,yoff) (lineto ,(+ 2 xoff) ,(+ 4 yoff))
(moveto ,(+ 1 xoff) ,yoff) (lineto ,(+ 3 xoff) ,(+ 4 yoff)))
and now it works like a charm. And that Scheme intro book looks like
exactly what I need to help head off similar confusions in the future.
"Relatively new to the language" is spot-on for me :-)
- Mike
On 12/22/2018 3:58 AM, Aaron Hill wrote:
On 2018-12-21 8:15 pm, Mike Stickles wrote:
But when I try to implement the numbers, I get errors no matter what I
do. This (while it doesn't work) shows what I'm trying to get to:
#(define-markup-command (double-box layout props xoff yoff) (number?
number?)
(interpret-markup layout props
#{
\markup {
\with-dimensions #'(0 . 0) #'(0 . 0)
\path #0.3 #'((moveto xoff yoff) (lineto (+ xoff 2) (+
yoff 4)) (moveto (+ xoff 1) yoff) (lineto (+ xoff 3) (+ yoff 4)))
}
#}
))
Any ideas on what I'm doing wrong?
You are hitting an common stumbling block in Scheme regarding
quoting. Urs has a great Scheme introduction book[1] online that
would be good reviewing as it sounds like you may be relatively new to
the language.
[1]: https://scheme-book.ursliska.de/
\path needs a list of commands, where an individual command consists
of a symbol (defining the particular command) and then its arguments,
which are typically just numbers.
To construct a suitable \path argument in Scheme, we use the list
function:
(list ((quote moveto) 1 2) ((quote lineto) 3 4))
This is the explicit list construction technique, and we are also
using the explicit invocation of quote. We need quote here because
"moveto" and "lineto" are symbols. We do not want the value behind
the symbols, just the symbols as things on their own.
Scheme (technically LISP) developed a number of shorthands for common
constructions. You can construct a list more succinctly this way:
'((moveto 1 2) (lineto 3 4))
The leading quote puts us in quote mode so that we can simply type
"moveto" by itself. We also no longer need to say list explicitly, as
we'll end up with a list. The numbers are technically being quoted
here, but a quoted number literal works.
But what if we need a variable? We cannot use the same construction,
because our variables will end up quoted rather than using the value
behind the name. One solution is to go back to the more explicit
invocation:
(list ('moveto a b) ('lineto c d))
Here we are still using the shortcut quote for the symbols, but
everything else will be resolved properly in this form. This is a
perfectly acceptable option, but some folks prefer the shorthand of
quoting. The alternate solution is quasi-quoting:
`((moveto ,a ,b) (lineto ,c ,d))
This one looks funny at first, but the difference is the use of the
grave as opposed to the apostrophe. This sets up a quasi-quoting mode
that behaves nearly identical to normal quoting, except we can use a
comma to "unquote". And here the variables will be evaluated as
expected.
-- Aaron Hill
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