Am 10.11.2016 um 08:53 schrieb Federico Bruni: > Hi > > As it's written in the documentation, "If there are more repeats than > there are alternate endings, the earliest repeats are given the first > alternative". > If I want to change this behaviour I should use manual repeats? Or > there's a smarter way? > > This is what I'd like to achieve: > > \repeat volta 4 { > c1 > } > \alternative { > { d1 } % 1st alternative > { e1 } % 2nd alternative > { f1 } % 3rd and 4th alternatives > } > > Thanks > Federico You will find this in the documentation for version 2.18.2 in chapter 1.4.1 long repeats: Your third and fourth alternative should be something like
\set Score.repeatCommands = #'((volta "3, 4") end-repeat) Regards Bernhard -- spitzhalde9 D-79853 lenzkirch bernhard.kle...@gmx.net www.b-kleine.com, www.urseetal.net - thunderbird mit enigmail GPG schlüssel: D5257409 fingerprint: 08 B7 F8 70 22 7A FC C1 15 49 CA A6 C7 6F A0 2E D5 25 74 09
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