basegfx/source/polygon/b2dtrapezoid.cxx | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
New commits:
commit 2cc09c4650c2fc6acc0157cd26acad248f32c5ac
Author: Andrea Gelmini <andrea.gelm...@gelma.net>
AuthorDate: Sat Nov 24 23:36:55 2018 +0100
Commit: Julien Nabet <serval2...@yahoo.fr>
CommitDate: Sun Nov 25 00:15:25 2018 +0100
Fix typo
Change-Id: I8e90b4592d041e63bd2efa914446db96dd293ac9
Reviewed-on: https://gerrit.libreoffice.org/63964
Reviewed-by: Julien Nabet <serval2...@yahoo.fr>
Tested-by: Julien Nabet <serval2...@yahoo.fr>
diff --git a/basegfx/source/polygon/b2dtrapezoid.cxx
b/basegfx/source/polygon/b2dtrapezoid.cxx
index 9bff42a0d0a6..9ddeed3309b9 100644
--- a/basegfx/source/polygon/b2dtrapezoid.cxx
+++ b/basegfx/source/polygon/b2dtrapezoid.cxx
@@ -588,7 +588,7 @@ namespace basegfx
{
// This is the central subdivider. The strategy is to use the
first two entries
// from the traversing edges as a potential trapezoid and do
the needed corrections
- // and adaptions on the way.
+ // and adaptations on the way.
// There always must be two edges with the same YStart value:
When adding the polygons
// in the constructor, there is always a topmost point from
which two edges start; when
@@ -661,7 +661,7 @@ namespace basegfx
B2DPoint aLeftEnd(aLeft.getEnd());
B2DPoint aRightEnd(aRight.getEnd());
- // check if end points are on the same line. If yes, no
adaption
+ // check if end points are on the same line. If yes, no
adaptation
// needs to be prepared. Also remember which one actually
is longer.
const bool bEndOnSameLine(fTools::equal(aLeftEnd.getY(),
aRightEnd.getY()));
bool bLeftIsLonger(false);
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