Hi Eike, > > And that is where I get stuck. > > I can imagine..
I wasn't surprised either ;-) > > > The first argument is on the stack, i.e. GetStackType() returns a type > and ScInterpreter::sp is 1. > > When I jump to the next argument to be evaluated, with aCode.Jump( > pJump[ nIdx ], pJump[ pJump[ 0 ] ] ), ScInterpreter::sp is 0 afterwards. > > Apart from that, aCode.Jump( pJump[ nIdx ], pJump[ pJump[ 0 ] ] ) looks > wrong to me, pJump[0] returns an offset into the RPN array, which can't be > used as an index for another pJump. I changed the code in my mail, the actual line reads aCode.Jump( pJump[ nIdx ], pJump[ nJumpCount ] ); and nJumpCount has the value of pJump[ 0 ]. > See also the description of formula::FormulaTokenIterator::Jump() in > include/formula/tokenarray.hxx > > For understanding it helps to step into such Jump() and see what it does > to the counters and on the subsequent iteration of the while loop in > ScInterpreter::Interpret() step into its condition where aCode.Next() is > executed and analyze what happens to the token array and counters. Will do. > > How do I get the argument I jumped to (that part works) on the stack to > be evaluated? > > I'm not sure at the moment. > [...] > > Basically both approaches would work, the latter might be even "easier" > (I know it's not easy at all) to code with what is already implemented. I will start digging and experimenting, which may take some time. Winfried _______________________________________________ LibreOffice mailing list LibreOffice@lists.freedesktop.org https://lists.freedesktop.org/mailman/listinfo/libreoffice
