source/text/scalc/01/04060111.xhp | 6 +++---
1 file changed, 3 insertions(+), 3 deletions(-)
New commits:
commit 8353d5baa0186d0774a9ddd598677b31bff5922c
Author: Eike Rathke <er...@redhat.com>
Date: Wed Jun 1 12:59:37 2016 +0200
eliminate the mentioning of locale dependent date string in ISLEAPYEAR
Rather use DATE() and "yyyy-mm-dd" ISO examples.
Change-Id: I41c9dc57167f8c70e8674fcd4b4038ab8e835141
diff --git a/source/text/scalc/01/04060111.xhp
b/source/text/scalc/01/04060111.xhp
index 89de050..7f6950c 100644
--- a/source/text/scalc/01/04060111.xhp
+++ b/source/text/scalc/01/04060111.xhp
@@ -49,12 +49,12 @@
<paragraph role="heading" id="hd_id3149566" xml-lang="en-US" level="2"
l10n="U" oldref="14">ISLEAPYEAR</paragraph>
<paragraph role="paragraph" id="par_id3150297" xml-lang="en-US" l10n="U"
oldref="15"><ahelp hid=".">Determines whether a year is a leap year.</ahelp> If
yes, the function will return the value 1 (TRUE); if not, it will return 0
(FALSE).</paragraph>
<paragraph role="heading" id="hd_id3148487" xml-lang="en-US" level="3"
l10n="U" oldref="16">Syntax</paragraph>
-<paragraph role="code" id="par_id3150205" xml-lang="en-US" l10n="U"
oldref="17">ISLEAPYEAR("Date")</paragraph>
+<paragraph role="code" id="par_id3150205" xml-lang="en-US" l10n="U"
oldref="17">ISLEAPYEAR(Date)</paragraph>
<paragraph role="paragraph" id="par_id3159239" xml-lang="en-US" l10n="U"
oldref="18">
-<emph>Date</emph> specifies whether a given date falls within a leap year. The
Date parameter must be a valid date according to the locale settings of
%PRODUCTNAME.</paragraph>
+<emph>Date</emph> specifies whether a given date falls within a leap year. The
Date parameter must be a valid date.</paragraph>
<paragraph role="heading" id="hd_id3149817" xml-lang="en-US" level="3"
l10n="U" oldref="19">Example</paragraph>
<paragraph role="paragraph" id="par_id3150786" xml-lang="en-US" l10n="CHG"
oldref="20">=ISLEAPYEAR(A1) returns 1, if A1 contains 1968-02-29, the valid
date 29th of February 1968 in your locale setting.</paragraph>
-<paragraph role="paragraph" id="par_idN107E7" xml-lang="en-US" l10n="CHG">You
may also use =ISLEAPYEAR("1968-02-29") or =ISLEAPYEAR("2/29/68").</paragraph>
+<paragraph role="paragraph" id="par_idN107E7" xml-lang="en-US" l10n="CHG">You
may also use =ISLEAPYEAR(DATE(1968;2;29)) or =ISLEAPYEAR("1968-02-29") giving
the date string in the ISO 8601 notation.</paragraph>
<paragraph role="paragraph" id="par_idN107EA" xml-lang="en-US"
l10n="CHG">Never use =ISLEAPYEAR(2/29/68), because this would first evaluate 2
divided by 29 divided by 68, and then calculate the ISLEAPYEAR function from
this small number as a serial date number.</paragraph>
</section>
<section id="years">
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