On 13.11.2013 14:02, waldo kitty wrote:
We don't need to invent the wheel again, because others have
solutions for that!
then why does this thread exist? O:)
I'll try to find what the usual way is to handle these problems: c++
Libraries for example?!
i don't know as i do not have that book... but since you have the
three routines available, can you please post what they return for the
two cases above??
I don't have my test app anymore, changed it a lot last days to follow
the discussion, but perhaps you have a look at my post from 12.11.2013,
21:56
[...]
Bart delivered code that calculates 29.02.2000 to 28.02.2001 = 1 Year.
And that looks reasonable to me!
but it is not, not really... 29.02 only comes around once every four
years... 29.02.leapyear to 28.02.leapyear+1 is one day short of a
year... if you were born on 29.02.1960, have you celebrated your
birthday 13 or 53 times? :)
That depends on the country , you're living, see
http://en.wikipedia.org/wiki/February_29#Births
Bart wrote:
I would actually say that in this particular case the diff is 1 Year...
(11 M + (28 days in feb in a non-leapyear = 1M) = 12M = 1 Y.
Soon we'll have working DateDiff function and my question will be
answered in
the end!
Thanks guys!!
i can, however, agree with the reasoning bart has given above... do
you agree with it? is that what you want to see?
I'm not the one to decide, but i need a function which provides widely
accepted results!
I'll google again.
which of the following is what you want to see??
2000-02-29 to 2001-02-28 is 0 yrs 11 mos 27 days (original)
2000-02-29 to 2001-02-28 is 0 yrs 11 mos 28 days (bart's fix)
2000-02-29 to 2001-02-28 is 1 yrs 0 mos 0 days (actually
desired?)
--
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