On Mon, 13 Dec 2021 22:34:55 +0200, "Dimitrios Chr. Ioannidis via lazarus" <lazarus@lists.lazarus-ide.org> wrote:
>Hi, > >???? 13/12/2021 10:01 ?.?., ?/? Bo Berglund via lazarus ??????: >> I am constantly using strip -s to reduce the size of the application binary >> and >> now I wonder if there is a way to make Lazarus NOT include the symbols in the >> first place? >> >> It seems like these are only used when debugging and that is started by >> clicking >> the green arrow button, so Lazarus should be able to figure out when the >> symbols >> are needed (for debug) and not add them when not needed... >> >> The reason I have for finding a way to do this is that the binary will be >> added >> to version control and then it may happen that one forgets the strip -s step >> before committing the state, thus sending an overly bloated binary into >> subversion. > >I suppose one way is to use Lazarus's build modes. > >i.e. > >Or if you don't want a script / batch, I think that you can add the copy >functionality for that "release" build mode to the "Project Options -> >Compiler Options -> Compiler Commands -> Execute after -> Command" and >leave only the build checkbox checked. With such a configuration, every >time you build that mode you'll have a stripped "release" binary which >will be copied to the location after the build ends . > This sounds like what I need. I looked at the project options and found that there is one box to enter the Execute after command. And checkboxes to set when it is used. But I would need *two* commands: - copy to the svn location - strip -s on that copy Does this mean I will have to use a batch file (on Windows) to perform both steps? How do I then transfer the name of the executable into that command? And will Lazarus use the standard binary or the one created in the release folder when debugging? -- Bo Berglund Developer in Sweden -- _______________________________________________ lazarus mailing list lazarus@lists.lazarus-ide.org https://lists.lazarus-ide.org/listinfo/lazarus
