On Wed, 7 Nov 2018 18:39:59 -0700 (MST), leledumbo via lazarus <lazarus@lists.lazarus-ide.org> wrote:
>> If I want to build the 64 bit version, where should I then put the 64 bit >binutils? > >Wherever -FD in your fpc.cfg points to (remember, fpc.cfg supports >conditionals). > >> The suggested path c:\freepascal\binutils\i386-win32\ seems incorrect. > >Why not? The binutils itself could still be 32-bit while generating 64-bit >binaries. Native 64-bit shouldn't be there, of course. So in fact I don't really need the 64 bit versions of the binutil files? I looked further down on the page I found and noted this regarding creation of the bat file used to build fpc: For crosscompiler to x86_64 add the following after the first make: make all OS_TARGET=win64 CPU_TARGET=x86_64 INSTALL_PREFIX=%myFPC% PP=%mybinutils%\ppc386.exe DATA2INC=%myFPC%\utils\data2inc.exe make crossinstall OS_TARGET=win64 CPU_TARGET=x86_64 INSTALL_PREFIX=%myFPC% PP=%mybinutils%\ppc386.exe DATA2INC=%myFPC%\utils\data2inc.exe It rather looks like I don't need two different Lazarus installations in order to build for both 32 and 64 bit windows, right? In that case should I not focus on the 64 bit version and have 32 bit as a crosscompile target? I.e. Use Lazarus 64 bit to sometimes create a 32 bit program through cross-compile. Now I am unsure of what kind of Lazaruses I really do have (4 versions at the moment). Is there a simple way to check if lazaus itself is 32 or 64 bit? For Lazarus the bat file looks like this: set myroot=c:\freepascal set myFPC=%myroot%\fpc\3.0.4 set mybinutils=%myroot%\binutils set PATH=%mybinutils%\i386-win32;%myFPC%\bin\i386-win32;%PATH% cd %myroot%\laz make clean all OPT="-glw2 -Xg" Will it build a 64 or 32 bit version of Lazarus? Looks like it uses 32 bit paths... -- Bo Berglund Developer in Sweden -- _______________________________________________ lazarus mailing list lazarus@lists.lazarus-ide.org https://lists.lazarus-ide.org/listinfo/lazarus
