At 03/02/2012 12:51 AM, Luiz Capitulino Wrote:
> On Mon, 27 Feb 2012 11:05:58 +0800
> Wen Congyang <we...@cn.fujitsu.com> wrote:
> 
>> When the host knows the guest is paniced, it will set
>> exit_reason to KVM_EXIT_GUEST_PANIC. So if qemu receive
>> this exit_reason, we can send a event to tell management
>> application that the guest is paniced.
>>
>> Signed-off-by: Wen Congyang <we...@cn.fujitsu.com>
>> ---
>>  kvm-all.c                 |    3 +++
>>  linux-headers/linux/kvm.h |    1 +
>>  monitor.c                 |    3 +++
>>  monitor.h                 |    1 +
>>  4 files changed, 8 insertions(+), 0 deletions(-)
>>
>> diff --git a/kvm-all.c b/kvm-all.c
>> index c4babda..ae428ab 100644
>> --- a/kvm-all.c
>> +++ b/kvm-all.c
>> @@ -1190,6 +1190,9 @@ int kvm_cpu_exec(CPUState *env)
>>                      (uint64_t)run->hw.hardware_exit_reason);
>>              ret = -1;
>>              break;
>> +        case KVM_EXIT_GUEST_PANIC:
>> +            monitor_protocol_event(QEVENT_GUEST_PANICED, NULL);
>> +            break;
> 
> The event alone is not enough, because the mngt app may miss it (eg. the panic
> happens before the mngt app connected to qemu).
> 
> A simple way to solve this would be to also add a new RunState called
> guest-panic and make the transition to it (besides sending the event).
> 
> A more general way would be to model this after -drive's werror/rerror 
> options,
> say guest-error=report|ignore|stop. When guest-error=stop, the mngt app will
> get a STOP event and can check the VM runstate to know if it's guest-panic.

OK, I will fix it.

Thanks
Wen Congyang

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