I have the Great Plains 2180 with a Prince P tip prop (52x48) and it burns 4.0 
US gallons per hour.
So Larry’s calculation is correct.
My header tank holds 10 US gallons so I usually flight plan for 2 hours with 30 
minute reserve .
Chris Gardiner
CGkRZ  KR2S

Sent from my iPhone

> On Jan 14, 2024, at 15:32, Larry Flesner via KRnet <krnet@list.krnet.org> 
> wrote:
> 
> 
>> On 1/14/2024 1:56 PM, Adam Deem via KRnet wrote:
>> I don't know about a fuel flow chart, but the math to calculate it is pretty 
>> simple.  The 2180 is 75 hp takeoff power at 3600RPM.  2180cc=.077cu ft.  
>> 3600RPM=1800 intakes/min for 138.6 cu ft/min or 8316 cu ft/hr.  8316x.08 
>> lbs/cu ft air=665.28 lbs air/hr. Correction for normally aspirated 
>> volumetric efficiency 665.28x.95=632 lb/hr.  632lbs air+60 lbs gasoline/hr = 
>> 100% power at 10.5:1 F/A ratio.  60lbs/6 lbs/gal = 10.0gph. Best power ratio 
>> would be 12:1.  You want your fuel system to deliver enough fuel in any 
>> scenario on takeoff (SL@10.5:1 standard day) with 150% safety margin to 
>> avoid starving the engine under worst case scenario (winter day with very 
>> low DA)
>> 
>> For that motor you'd want to run a fuel flow system test and verify it can 
>> deliver at least 15gph.  For comparison, my electric pump fed system (Facet 
>> 3psi cube pumps) delivers a verified 19gph through the system.  I hope this 
>> is helpful.
>> 
>> Adam Deem
> 
> ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
> 
> A bit less cumbersome math / rule of thumb  that is quite accurate for the 
> type of engines we use is 1/2 pound of fuel per horsepower per hour.  The 
> 0-200 at 100 hp / 2 = 50 pounds of fuel / 6 ppg = 8.33 gph at full throttle 
> at takeoff if its actually producing 100 hp.  A VW producing 75 hp on takeoff 
> would be 75/2=37.5 / 6ppg = 6.25 gph.   Multiply that number by 1.5 for 
> minimum acceptable fuel flow.  This holds true for any % of power hp fuel 
> flow.
> 
> The 0-200 for example at 65% power at cruise is 65hp / 2 =32.5 pounds of fuel 
> / 6 =5.42 gph at an acceptable fuel / air mixture (moderate lean mixture of 
> 14:1)
> 
> A 75 hp VW at 65% power cruise = 48.75 hp / 2 = 24.37 pounds of fuel / 6 = 4 
> gph fuel burn.  I've never flown a VW engine but I'm guessing that is pretty 
> close.
> 
> Larry Flesner
> 
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