Well actually Jeff, the current in the circuit stays the same. Refer http://www.allaboutcircuits.com/vol_1/chpt_5/2.html
The brightness is a function of power (watts) which equals volts times amps. Since amps remain the same, a resistor/rheostat drops the voltage across the bulb thus dimming it. The associated voltage drop across the resistor times the amps equals the watts that the resistor must give off as heat. The sum of the voltage drops must equal the voltage of the battery (12volts). In summary, electrons out of a battery terminal equals electrons in at the other. Those little fizzers have to go somewhere :-). John Martindale 29 Jane Circuit Toormina NSW 2452 Australia ph:61 2 6658 4767 m:0403 432179 email:john_martind...@bigpond.com -----Original Message----- From: krnet-boun...@mylist.net [mailto:krnet-boun...@mylist.net] On Behalf Of Jeff York Sent: Wednesday, 19 October 2011 2:46 AM To: KRnet Subject: Re: KR> POT OHM OR K? Ok, It has been a long time since I was in Electrical Engineering 101. .....snip
