https://bugs.kde.org/show_bug.cgi?id=364280
--- Comment #7 from Thomas Lübking <thomas.luebk...@gmail.com> ---
The function prefers lower screens, ie. if a window intersects screen 0 & 1, it
will determine the window on screen 0, even if there's only a single
intersecting pixel.
Windows can be legally on multiple screens because they either cross the border
or because the screens overlap ("cloned")
Even if you want to ignore the latter case and only support bijective
assignments, you might want to test the (frame)geometry().center() (which
implies the biggest share on regular™ setups) instead.
Depending on the usecase, you may also first test availableGeometry() to ensure
you do not estimate a window on a screen where it's (completely) covered by
(strutting) panels if it's pot. also on another screen. (It can still be below
non-strutting panels despite such test, though)
For a general geometry comparism (is this window on this screen) you should
test the ::frameGeometry(), users tend to consider them a unit.
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