maybe with reduce ?
```
function mapeBase_v4(A::Vector{Float64}, F::Vector{Float64})
function abscount(prev, current)
current[2] == 0.0 && return prev
index, item = current
(prev[1] + abs( 1 - F[index] / item), prev[2] + 1)
end
reduce(abscount, (0.0, 0), enumerate(A))
end
```
2016-10-25 9:43 GMT+02:00 Jeffrey Sarnoff <[email protected]>:
> This may do what you want.
>
> function mapeBase_v3(actuals::Vector{Float64}, forecasts::Vector{Float64})
> # actuals - actual target values
> # forecasts - forecasts (model estimations)
>
> sum_reldiffs = sumabs((x - y) / x for (x, y) in zip(actuals, forecasts) if
> x != 0.0) # Generator
>
> count_zeros = sum( map(x->(x==0.0), actuals) )
> count_nonzeros = length(actuals) - count_zeros
> sum_reldiffs, count_nonzeros
> end
>
>
>
>
> On Tuesday, October 25, 2016 at 3:15:54 AM UTC-4, Martin Florek wrote:
>>
>> Hi all,
>> I'm new in Julia and I'm doing refactoring. I have the following function:
>>
>> function mapeBase_v1(A::Vector{Float64}, F::Vector{Float64})
>> s = 0.0
>> count = 0
>> for i in 1:length(A)
>> if(A[i] != 0.0)
>> s += abs( (A[i] - F[i]) / A[i])
>> count += 1
>> end
>> end
>>
>> s, count
>>
>> end
>>
>> I'm looking for a simpler variant which is as follows:
>>
>> function mapeBase_v2(A::Vector{Float64}, F::Vector{Float64})
>> # A - actual target values
>> # F - forecasts (model estimations)
>>
>> s = sumabs((x - y) / x for (x, y) in zip(A, F) if x != 0) # Generator
>>
>> count = length(A) # ???
>> s, countend
>>
>>
>> However with this variant can not determine the number of non-zero elements.
>> I found option with length(A[A .!= 0.0]), but it has a large allocation.
>> Please, someone knows a solution with generator, or variant v1 is very good
>> choice?
>>
>>
>> Thanks in advance,
>> Martin
>>
>>
