also it gives me error
El martes, 4 de octubre de 2016, 17:53:52 (UTC+2), Kristoffer Carlsson
escribió:
>
> Did you mean
>
> Base.show(io::IO, n::One) = print(io, n.*o*)?
>
> On Tuesday, October 4, 2016 at 4:21:57 PM UTC+2, alx wrote:
>>
>> Hi, I do wrong, please
>>
>> --
>> using PyCall
>>
>> type One
>> o::PyObject
>> One() = new( PyObject(1) )
>> end
>>
>> Base.show(io::IO, n::One) = print(io, n)
>>
>> n=One()
>>
>> Error showing value of type One:
>> ERROR: StackOverflowError:
>> in print(::IOContext{Base.Terminals.TTYTerminal}, ::One) at ./strings/io
>> .jl:7
>> in print(::IOContext{Base.Terminals.TTYTerminal}, ::One) at ./strings/io
>> .jl:8 (repeats 48 times)
>>
>>
>>
>>
