The parseint function is not vectorized – you need to apply parseint to
each character using map or a comprehension. In your case, you might as
well just subtract '0' from each character.
On Mon, Jun 15, 2015 at 2:22 PM, James Byars <jimmyby...@gmail.com> wrote:
> Thank you for the suggestion. I tried to use parseint on the Char array
> and got the following error:
>
> `parseint` has no method matching parseint(::Array{Char,1})
>
>
> On Monday, June 15, 2015 at 1:02:21 PM UTC-4, Huda Nassar wrote:
>>
>> You can use the parseint function:
>>
>> *julia> **a = '3'*
>>
>> *'3'*
>>
>> *julia> **typeof(a)*
>>
>> *Char*
>>
>> *julia> **b = parseint(a)*
>>
>> *3*
>>
>> *julia> **typeof(b)*
>>
>> *Int64*
>>
>>
>>
>> On Monday, June 15, 2015 at 12:39:14 PM UTC-4, James Byars wrote:
>>>
>>> Hey all,
>>>
>>> I am working through some Project Euler problem (#008) about searching
>>> through a number to determine the greatest product of
>>> thirteen adjacent numbers. Here is a code snippet:
>>>
>>> n = 12
>>> numb_strg = "82166370484403199890008895243450658541227588666881"
>>> string_post = length(numb_strg) - n
>>> string_post = 0
>>>
>>> When I run this command:
>>> *collect(numb_strg[(string_post+1):(string_post**+n)])*
>>>
>>> I get a character vector.
>>>
>>> 12-element Array{Char,1}:
>>> '8'
>>> '2'
>>> '1'
>>> '6'
>>> '6'
>>> '3'
>>> '7'
>>> '0'
>>> '4'
>>> '8'
>>> '4'
>>> '4'
>>>
>>>
>>> However, if I attempt to convert it to a integer array. I get the
>>> following array.
>>>
>>> 12-element Array{Int64,1}:
>>> 56
>>> 50
>>> 49
>>> 54
>>> 54
>>> 51
>>> 55
>>> 48
>>> 52
>>> 56
>>> 52
>>> 52
>>>
>>>
>>> If I subtract 48 from the each element in the array, I get the correct
>>> number. Is there any reason for the odd conversion from character to
>>> integer (or float)? My primary language is R and I am using Project Euler
>>> to learn Julia.
>>>
>>>
>>> Thanks,
>>>
>>>
>>> James
>>>
>>>
