Oh nice, I just did factorial(1000000) and it actually produced an answer. What kind of arcane magic is used to make this possible?
Regards, C. F. Baptista On 13 January 2015 at 04:22, Erik Schnetter <[email protected]> wrote: > julia> factorial(big(171)) > > 1241018070217667823424840524103103992616605577501693185388951803611996075221691752992751978120487585576464959501670387052809889858690710767331242032218484364310473577889968548278290754541561964852153468318044293239598173696899657235903947616152278558180061176365108428800000000000000000000000000000000000000000 > > > On Jan 12, 2015, at 22:17 , Isaiah Norton <[email protected]> > wrote: > > > > julia> factorial(big(21)) > > 51090942171709440000 > > > > (Julia doesn't auto-promote) > > > > On Mon, Jan 12, 2015 at 10:10 PM, Carlos Baptista <[email protected]> > wrote: > > I understand that factorial(21) is quite a large number and therefore an > OverflowError is perfectly understandable. However, with Octave I can go up > to factorial(170) (if I go higher I receive Inf). Is there a way to go > beyond factorial(20) in Julia? > > -- > Erik Schnetter <[email protected]> > http://www.perimeterinstitute.ca/personal/eschnetter/ > > My email is as private as my paper mail. I therefore support encrypting > and signing email messages. Get my PGP key from http://pgp.mit.edu/. > >
