I think you need `julia.call` instead of `julia.run`. On Tue, Sep 9, 2014 at 7:16 AM, Uwe Fechner <uwe.fechner....@gmail.com> wrote:
> Hello, > > I have a function, that is running much faster in Julia then in Python. > > Now I want to call it from my (large) Python program. > > I tried to do this, using pyjulia from > https://github.com/JuliaLang/pyjulia . > > I am using Ubuntu 12.04, 64 bits and Julia 0.3 and tried to install > pyjulia in the following way: > > cd ~ > mkdir 00Software > cd 00Software > git clone https://github.com/JuliaLang/pyjulia.git > cd pyjulia > sudo python setup.py install > > Then I started ipython and tried the following code: > > import julia > j=julia.Julia() > j.run("2+2") > > I get the following error message: > > In [3]: j.run("2+2") > --------------------------------------------------------------------------- > RuntimeError Traceback (most recent call last) > <ipython-input-3-4f45159364ef> in <module>() > ----> 1 j.run("2+2") > > RuntimeError: Julia exception: MethodError(run,("2+2",)) > > In [4]: > > Any idea what is going wrong? > > Best regards: > > Uwe Fechner >
