Thanks to both for the responses.
Related questions: how does one turn a 2-dimensional array into a
1-dimensional array of row arrays? Also, the default behavior of julia
is that a row of a 2-dimensional array is also a 2-dimensional array.
Would anyone comment why this is the case? Should it better be a
1-dimensional array?
On 2014年08月07日 19:59, Ethan Anderes wrote:
Here is another one…slightly different:
|in(x[1,:], Matrix[x[k,:] for k=1:size(x,2)] )
|
To be honest, the custom for loop is probably your best bet in terms
of performance:
|function isrow(row, x::Matrix)
for k=1:size(x,1)
if row == x[k,:]
return true
end
end
false
end
|
On Thursday, August 7, 2014 1:36:08 AM UTC-7, Gunnar Farnebäck wrote:
Is this easy enough?
julia> x = reshape(1:16, 4, 4)
4x4 Array{Int64,2}:
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
julia> a = x[1,:]
1x4 Array{Int64,2}:
1 5 9 13
julia> [a == x[k,:] for k = 1:size(x,1)]
4-element Array{Any,1}:
true
false
false
false
julia> any([a == x[k,:] for k = 1:size(x,1)])
true
julia> find([a == x[k,:] for k = 1:size(x,1)])
1-element Array{Int64,1}:
1
Den torsdagen den 7:e augusti 2014 kl. 06:09:23 UTC+2 skrev K leo:
julia> x
4x4 Array{Int64,2}:
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
julia> in(x[1,:], x)
false
julia> x[1,:]
1x4 Array{Int64,2}:
1 5 9 13
How can I check if x[1,:] is in x easily? And with the row
index in x?
