Or you can use
typealias FPArray{T<:FloatingPoint} Array{T}
foo(a::FPArray, b::FPArray) = a+b
to get the same effect (foo will still apply when the element types of aand
b are different).
Perhaps we could introduce a syntax to create such a covariant typealias on
the fly, e.g.
const FPArray2 = Array{<:FloatingPoint}
would work the same as FPArray above (though with an anonymous/hidden type
parameter).
Then the example could be written
foo(a::Array{<:FloatingPoint}, b::Array{<:FloatingPoint}) = a+b
if you don't want to define the typealias first.
On Sunday, 25 May 2014 17:44:26 UTC+2, Pierre-Yves Gérardy wrote:
>
> On Sunday, May 25, 2014 5:10:49 PM UTC+2, James Crist wrote:
>>
>> Yeah, that's what I've been using. My issue with it is that the
>> declarations get long for functions with more than 2 arrays. Was hoping
>> there was a more concise way.
>>
>
> You can use typealias Fp FloatingPoint , then
>
> function foo{T1<:Fp, T2<:Fp}(a::Array{T1}, b::Array{T2})
>
>
