I mean that in Safari and Firefox, the code produces:
<input id="testId" class="testClass" type="checkbox" style="border: 1px
solid rgb(96, 32, 86); background-color: rgb(255, 0, 217); color: rgb(0, 0,
0); width: 123px;">
Whether there is a visual modification or not, Safari at least tells me that
the background-color is what I set it to be. Firefox tells me it is white.
I was simply wondering whether or not I should waste time trying to figure
out a work-around or not. It sounds like this is just the way it is because
that is how Firefox works. Yes?
2009/12/23 Šime Vidas <sime.vi...@gmail.com>
>
> > So, on Safari, the code for the checkbox passes. On Firefox, it does
> not.
> > Funny thing, the <input> element has a style for the background color,
> but
> > .css('background-color') is not returning the color I set. It is
> returning
> > rgb(255,255,255).
>
>
> What do you mean by "in Safari the code passes" ?
> From my own testing, setting a background-color on checkboxes has
> visual effect only in IE and Opera... but not FF, Safari and Chrome.
>
> Also, what do you mean by "the input element has a style for the
> background color" ?
>
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