Re: [jQuery] plugin good structure with params

[Rafał Pocztarski]

2009/12/10 Imre Farkas <farkasimr...@gmail.com>:
> Now when i call  i do it so
>
> <script type="text/javascript">
> $(document).ready(function() {
>        $("#progresbar-bar").hide();
>        $("#procent").hide();
>        $("#progresbar-bar").progresbar(procent=0,manual=false);
> });
> </script>
>
> My question: how can i make this to be a good writed structured
> plugin, and to call like
>
>
> <script type="text/javascript">
> $(document).ready(function() {
>        $("#progresbar-bar").hide();
>        $("#procent").hide();
>        $("#progresbar-bar").progresbar({
>               procent:0,
>               manual:false)};
> </script>
>

Instead of using positional arguments:

function(procent_val, manual) {
    var non_dinamic = manual;
    var procent = procent_val;
    ...
}

you can use an object to pass them by name:

function(arguments) {
    var non_dinamic = arguments.manual;
    var procent = arguments.procent_val;
    ...
}

By the way, when you call your function:

.progresbar(procent=0, manual=false);

you are also setting procent and manual variables in the local scope
of the caller. It is equivalent to:

procent = 0;
manual = false;
.progresbar(procent, manual);

What you probably wanted to do was just:

.progresbar(0, false);

When you use positional arguments you don't have to know their name.
When you use named arguments (using an object in JavaScript) you don't
have to remember their position and it's easier to add arguments
later, and it's also easier to call the function when some of them are
optional.

Rafał Pocztarski