nothing here looks like it would cause a syntax error. Maybe the
problem is in your formLogin() function?
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Nov 19, 2009, at 2:00 AM, viperasi wrote:
Whether jquery-1.3.2.js or jquery-1.3.2.min.js,i always got the
error.Other browsers without error.
Below is the code:
$(function(){
$('#username').keydown(function(event){
if(event.keyCode==13){
formLogin();
}
});
$('#password').keydown(function(event){
if(event.keyCode==13){
formLogin();
}
});
$('#valicode').keydown(function(event){
if(event.keyCode==13){
formLogin();
}
});
});
Can anyway help me please? I think it's something really simple and
I'm just being stupid.
Many thanks for reading and sorry for my poor English.
................................................................
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