its not installed, the functions break the script and I'm now aware that this isn't obvious when its done in an ajax call :) thanks!
On Aug 27, 12:22 pm, Leonard Martin <leonard.mar...@gmail.com> wrote: > Have you also tried accessing your PHP page directly and copying it's > output intohttp://www.jsonlint.com? > > I'd also double check your server has the JSON module for PHP > installed, just to be sure ;-) > > On Aug 27, 4:45 pm, MorningZ <morni...@gmail.com> wrote: > > > > > I would suggest using Firefox and FireBug to "watch" what comes back > > from your $.getJSON call... because that will indicate that your JSON > > is indeed valid, because if it isn't, you'll never make it into the > > success event > > > On Aug 27, 11:01 am, sso <strongsilent...@gmail.com> wrote: > > > > I need to return several values and I'd rather do it all in one ajax > > > call. However there doesn't seem to be anything in data. Perhaps I'm > > > way off here. > > > > I appreciate any guidance you can give me. Thanks :) > > > > This is my jquery > > > $('#cart-pulldown').livequery('click', function(event){ > > > $.getJSON(siteurl + "home/aj/showCart/", {}, > > > function(data){ > > > alert(data); > > > }); > > > }); > > > > This is the ajax in my PHP > > > $tmp = ""; > > > foreach($_SESSION['cart'] as $key > > > =>$line){ > > > $tmp .= $key . " ..... " . $line > > > . "<br />\n"; > > > } > > > $tmp .= '<div><span id="clearList">Clear > > > List</span></div>'; > > > echo json_encode($tmp);
