Yes, you (wheatstraw) just need to remember that attr('src') returns a
string and *not* a reference to the src attribute.
On Aug 26, 5:16 pm, amuhlou <amysch...@gmail.com> wrote:
> I think keeping the source in a variable is the key here, try this:
>
> $('li.clickable').hover(function() {
> var newsrc = $(this).find('img').attr('src').replace
> ("_off","_over");
> $(this).find('img').attr({src: newsrc});}, function() {
>
> var oldsrc = $(this).find('img').attr('src').replace
> ("_over","_off");
> $(this).find('img').attr({src: oldsrc});
>
> });
>
> On Aug 26, 3:44 pm, wheatstraw <psurr...@gmail.com> wrote:
>
> > OK! we're close...
>
> > If I attach this to a variable and echo it out, it give's me the
> > correct string. The _off is replaced with _over and the other way
> > around. As I have it below, on hover, the image will not change, no
> > errors (firebug), just doesn't do anything.
>
> > $('li.clickable').hover(function() {
> > $(this).find('img').attr('src').replace("_off","_over");},
> > function() {
>
> > $(this).find('img').attr('src').replace("_over","_off");
>
> > });
