Hi,
Just implement the falg so that specific data will show into the div.
For Example:
$.ajax({
type: "POST",
url: "some.php?ajx=1",
data: "name=test",
success: function(data){
$("#div").html(data);
}
});
in file some.php
if($_REQUEST['ajx'] == 1)
{
echo 'content will come here.';
}
else
{
echo 'elese print the content like this';
}
Regards,
Anurag Pal
On Tue, Aug 18, 2009 at 3:04 PM, ghost2008 <mariobei...@googlemail.com>wrote:
>
> Hello there,
>
> I am not sure, if this works. I make a function call with the ajax
> option of jquery:
>
> $.ajax({
> type: "POST",
> url: "some.php",
> data: "name=test",
> success: function(data){
> $("#div").html(data);
> }
> });
>
> If I try this, the whole response data is shown in the specific #div.
> Is there any possibility to load only the content of "#div" from
> some.php?
>
> Thanks for your answers.
> Regards
