Yeah sure...here's the code:
$("button.save").click(function(){
var action = $(this).parent("form").attr("action");
var i = 0;
var size = $(this).siblings("input, select").size();
var nameArray = [];
var valueArray = [];
for (i=0;i<size;i++){
nameArray[i] = $("[name]:eq("+i+")").attr("name");
valueArray[i] = $("[name]:eq("+i+")").val();
}
var n = 5;
for (n in nameArray){
if(postThis == null){postThis = nameArray[0] + ': "' +
valueArray
[0] + '"'}
if(n > 0){var postThis = postThis + ',' + nameArray[n]
+ ': "' +
valueArray[n] + '"';}
//alert(n);
//alert(nameArray[n]);
//alert(valueArray[n]);
}
postThis = "{" + postThis + "}";
alert(postThis);
/*postThis = {Name:"Jimmy", Username:"Something",
Password:"something", Email:"somethth...@someplace.com"};
$.post(action, postThis, function(data) {
alert('done');
});*/
$.post(action, postThis, function(data){
alert("done");
});
return false;
});
Thanks
On Aug 12, 4:44 pm, James <james.gp....@gmail.com> wrote:
> It's probably possible to not need to use it. But you're not revealing
> much code to us it's difficult to help.
> Can you show us how what you put in your variable 'postThis'? How do
> you create this?
> If you have postThis as a JSON object to begin with, you don't need
> the json2.js file.
>
> On Aug 12, 11:37 am, cz231 <cz2...@gmail.com> wrote:
>
> > And there's no way to do it without adding another js file?
>
> > I ask because for this project is pretty important to keep the number
> > of requests down.
>
> > On Aug 12, 3:43 pm, James <james.gp....@gmail.com> wrote:
>
> > > The type you want is JSON (an object).
>
> > > Include this Javascript file here:http://www.json.org/json2.js
>
> > > Then use the JSON.parse() function which will convert a String to a
> > > JSON object. The String has to have a format like a JSON object for it
> > > to work properly.
>
> > > var postData = JSON.parse(postThis);
> > > $.post('somefile.php', postData, function(data) {
> > > alert('done');
>
> > > });
>
> > > On Aug 12, 9:28 am, cz231 <cz2...@gmail.com> wrote:
>
> > > > I think I know the problem...My postThis variable ends up being just
> > > > one big string. How do I convert it to the correct type? (I'm not even
> > > > sure what type is correct)
>
> > > > On Aug 12, 2:00 pm, James <james.gp....@gmail.com> wrote:
>
> > > > > I don't see the problem...
>
> > > > > Something like this should work:
>
> > > > > var action = 'somepage.php';
> > > > > var postThis = {Name:"Jimmy", Username:"Something",
> > > > > Password:"something", Email:"someth...@someplace.com"};
> > > > > $.post(action, postThis, function(data) {
> > > > > alert('done');
>
> > > > > });
>
> > > > > Otherwise, post your real code for us to see what's going on.
>
> > > > > On Aug 12, 8:52 am, cz231 <cz2...@gmail.com> wrote:
>
> > > > > > Oops. I'm sorry.
>
> > > > > > action is the url to be posted to, and postThis is equal to: Name:
> > > > > > "Jimmy", Username: "Something", Password:
> > > > > > "something", Email: "someth...@someplace.com"
>
> > > > > > On Aug 12, 12:51 pm, Jörn Zaefferer <joern.zaeffe...@googlemail.com>
> > > > > > wrote:
>
> > > > > > > What values do the variables "action" and postThis contain? You
> > > > > > > describe them as "actions", isn't telling me anything.
>
> > > > > > > Jörn
>
> > > > > > > On Wed, Aug 12, 2009 at 7:40 PM, cz231<cz2...@gmail.com> wrote:
>
> > > > > > > > Hi,
>
> > > > > > > > I'm using AJAX to submit a form. I'm using the POST method.
> > > > > > > > Example:
>
> > > > > > > > $.post(action, postThis);
>
> > > > > > > > Both action and postThis are actions. Action is the URL and
> > > > > > > > postThis
> > > > > > > > is the data to be submitted. Right now, this isn't working. I
> > > > > > > > know I
> > > > > > > > can pass the action variable because that has always been
> > > > > > > > working. But
> > > > > > > > how do I put the parameters there as a variable? It will work
> > > > > > > > if I
> > > > > > > > express the parameters like this:
>
> > > > > > > > $.post(action, {Name: "Jimmy", Username: "Something", Password:
> > > > > > > > "something", Email: "someth...@someplace.com" });
>
> > > > > > > > Any help would be greatly appreciated.
