yeah haha let me re-do:
$("table#id tr:first-child").each(function(){
$(this).attr("attribute","value");
});
try that. I am thinking that the tr:first-child should return the TD
for every TR in the table. Im not sure how this will work if you have
nested tables. I'm at work so I cant spend the time to test the code
before hand.
On Jun 24, 10:50 am, MikeyJ <m.en...@gmail.com> wrote:
> Thx Matthew! Great explanation.
>
> I probably should have worded one thing a bit differently...I'd like
> to set this attribute for "the first TD in each TR for EVERY TR in an
> entire table". I'm sure this changes things a tiny bit?
>
> Mike
>
> On Jun 24, 10:43 am, Matthew <mvbo...@gmail.com> wrote:
>
> > when you use this code $("tr td") it would create an array of all
> > those td's in the tr. So then we just need to cycle through the first
> > two and set the attribute then break the cycle.
>
> > var counter = 0;
> > $("tr td").each(function(){
> > $(this).attr("attribute","value");
> > counter++;
> > if(counter > 1) { break; } // after the first two td's stop
> > the iteration through all the td's.
>
> > });
>
> > You can be more specific with what tr you use or you could use a table
> > with a certain class or id:
>
> > $("table.class tr td").each(........
>
> > hope this helps.
>
> > On Jun 24, 10:26 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > > Hi All,
>
> > > I'd like to set the align attribute of only the first TD in a TR for
> > > an entire table but am not sure how to address them all in one go.
> > > Probably an Nth child thing or similar but not sure!
>
> > > Thx,
> > > Mike
