Hi again, did some testing by creating a valid URL parameter string and use that in the data and that actually did work (too my surprise).
if this is the case,.. then how does one transmit a json object?? and why is there a dataType = "json" in jQuery $.ajax?? regards, Peter On Wed, Jun 3, 2009 at 4:19 PM, Peter Marino <marino.pe...@gmail.com> wrote: > Hi Jakob, > if I understand the documentation the type parameter is used to tell jQuery > how you > want to have the data received on the server side. The dataType tells > jQuery what kind > of data you will be transmitting. (unless I have totaly mis understood it > and that would > explain my 30 hours of working on it with no result). > > regards, > Peter > > On Wed, Jun 3, 2009 at 8:39 AM, Dam <jakob.a....@gmail.com> wrote: > >> >> Hi, >> >> It's kind of odd what you do: namely input nested JSON data as URI >> parameters in a GET request. >> It doesn't make sense to URL encode your data that has a nested >> object, so probably jQuery skips it. >> >> URI parameters are only key/value paris. >> >> POST can be used if you want to include arbitrary data in the body of >> a request. >> >> Maybe something like this instead (assuming you don't want to POST >> data on the server) >> >> $.ajax({ >> url: "http://localhost/test/gui/ajax_member.php", >> type: "GET", >> data: 'mybutt=' + data.mybutt + '&member=' + data.member.name, >> cache: false, >> dataType: "json", >> ... >> }) >> >> regards Jakob >> > > > > -- > Power Tumbling - http://www.powertumbling.dk > OSG-Help - http://osghelp.com > -- Power Tumbling - http://www.powertumbling.dk OSG-Help - http://osghelp.com