Hil all ,i tried something like , When i select the drop down value , that value related content will display into listbox,
But when i select another value , old one will not disabled , how to disable the old one , <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title> Test for UKATN</title> <script src="jquery-1.2.6.min.js" type="text/javascript"></script> <script type="text/javascript"> function show_place(str){ $.ajax({ type: "POST", url: "load_place_div.php", data: "place="+str, success: function(html){ $("#results").append(html); } }); } </script> </head> <body> <?php mysql_connect("localhost","root","admin"); mysql_select_db("test"); $load_location_query = "SELECT * FROM going_from "; $load_location_result = mysql_query($load_location_query); ?> <form method="post"> <select id="cmb_location" name="cmb_location" onchange="show_place(this.value)"> <option value="">Select</option> <?php while($row = mysql_fetch_object($load_location_result)){ $location_name = $row->location_name; $location_id = $row->from_id; ?> <option value="<?php echo $location_id;?>"><?php echo $location_name;?></option> <?php } ?> </select> <div id="results"></div> <input type="submit" name="btn" /> </form> <?php if(isset($_REQUEST['place_name']) && $_REQUEST['place_name']!=""){ print $_REQUEST['place_name']; } ?> </body> </html> load_place_div .php File <?php mysql_connect("localhost","root","admin"); mysql_select_db("test"); if(isset($_REQUEST['place']) && $_REQUEST['place'] != ""){ $place = $_REQUEST['place']; $load_query = "SELECT place_name,fromID FROM place_name WHERE fromID = '$place' "; $load_result = mysql_query($load_query); ?> <select multiple="multiple" name="place_name" > <?php while($row = mysql_fetch_object($load_result)){ $place_name = $row->place_name; $place_id = $row->fromID; ?> <option value="<?php echo $place_id; ?> "><?php echo $place_name; ?></option> <?php } ?> </select> <?php } ?> -- உங்கள் நண்பன் பரணி குமார் Regards B.S.Bharanikumar POST YOUR OPINION http://bharanikumariyerphp.site88.net/bharanikumar/