Hey Karl.
THANKS! Sorry, i'm a real beginner on this. This is a good lesson for
me!
Greatly appreciate.
Liming
On Apr 29, 6:04 pm, Karl Swedberg <k...@englishrules.com> wrote:
> Hi Liming,
>
> Just a child combinator rather than a descendant combinator:
>
> $("div[id ^= 'childtest_' ] > :first-child").each(function() {
> alert( $(this).attr("id") )
>
> });
>
> --Karl
>
> ____________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On Apr 29, 2009, at 4:14 PM, Liming wrote:
>
>
>
> > my bad. I was changing it around. It shoudl be
>
> > $("div[id ^= 'childtest_' ] :first-child").each(function() {
> > alert( $(this).attr("id") )
>
> > });
>
> > On Apr 29, 3:55 pm, MorningZ <morni...@gmail.com> wrote:
> >> I don't understand.. there's no where that you are using ":first-
> >> child" like your subject line says
>
> >> On Apr 29, 11:43 am, Liming <lmxudot...@gmail.com> wrote:
>
> >>> Hello all, I have a lay out like so
>
> >>> <div id="childtest_toprow">
> >>> <div id="subtest_1">
> >>> <div id="subtest_1_1"></div>
> >>> <div id="subtest_1_2"></div>
> >>> </div>
> >>> </div>
> >>> <div id="subtest_2">
> >>> </div>
> >>> </div>
>
> >>> I want to select the first child of "childtest_toprow" which is
> >>> "subtest_1"
>
> >>> when i do
>
> >>> $("div[id ^= 'childtest_' ] :nth-child(1)").each(function() {
> >>> alert( $(this).attr("id") )
>
> >>> });
>
> >>> I get "subtest_1" AND "subest_1_1"
>
> >>> what am I doing wrong?
>
> >>> Thanks
>
> >>> ps: i'm using firefox 3 and IE 7
