This is great. Thanks so much! For some reason the DIV for the "commentWrapper" is not working on the render page..here is what I have:
</head> <body> <input name="u" id="u" type="hidden" value="A_u3V" /> <a href="#" id='goComment'>go</a> <div id="commentWrapper"></div> </body> </html> It appears the code you provided amends the DIV. Any thoughts would be great? On Apr 28, 5:11 pm, Jake McGraw <jmcgr...@gmail.com> wrote: > You've got quite a few errors in both your JavaScript and PHP, which > probably explains the lack of answers. Utilizing AJAX using jQuery and > PHP can be a bit confusing at first, I've tried to make some sense of > what you're doing here: > > http://snipt.net/jakemcgraw/jquery-listserv-answer-ajax-comment-list > > - jake > > On Tue, Apr 28, 2009 at 12:17 PM, fluxUX <martine...@gmail.com> wrote: > > > I want to display an unordered list of comments from my echoed JSON > > result using this jQuery code block: > > > $("#goComment").click(function(){ > > > bigComment = $("#bigComment").val(); > > > $.post("i-upComments.php", { //this inserts the > > comment > > into the 'comments' table in the DB > > > bigComment: bigComment, > > u: u, > > > }, function(data){ > > > //display the list of comments as a unordered list - LI > > > }); > > > }); > > > ----------------- > > Here is my PHP: > > > <?php > > > include_once("db.php"); > > > $u = 'Jl6XR'; > > > $sql = "SELECT * FROM bigNest INNER JOIN comments ON comments.u = > > bigNest.uid"; > > > $result = mysql_query($sql); > > > while($array = mysql_fetch_array($result)) { > > > $bigtitle = $array[bigtitle]; > > $bigbody = $array[bigbody]; > > $comments = $array[comments]; > > } > > > $val = array("bigtitle" => $bigtitle, > > "bigbody" => $bigbody, > > "comments" => $comments, > > > ); > > > $output = json_encode($val); > > echo $output."\n"; > > > ?>
