It looks like you've got the function keyword inside the slide callback
which is where you want to call the myAjax function, not declare it. I think
you want something like this
function myAjax(val1, val2) {
// do something with ajax and the two values passed in, val1 and val2
}
$(function() {
$("#slider-range").slider({
slide: function(event, ui) {
myAjax(ui.values[0], ui.values[1]);
}
});
});
- Richard
On Mon, Mar 16, 2009 at 1:33 PM, borg <markk1...@gmail.com> wrote:
>
> Hi I am a novice to javascript and jquery developer trying to pass
> slider values to an AJAX script. My slieder looks like this:
>
> $(function() {
> $("#slider-range").slider({
> range: true,
> min: -10,
> max: 66,
> //values: [Math.pow(10,2), Math.pow(10,5)],
> values: [20, 30],
> slide: function(event, ui) {
> $("#amount").val('' +
> (Math.round(Math.pow(10,(ui.values[0] /
> 10))) ) + ' - ' + (Math.round(Math.pow(10,(ui.values[1] / 10))) ));
> }
> });
> //$("#amount").val('' + $("#slider-range").slider("values",
> 0) + ' -
> ' + $("#slider-range").slider("values", 1));
>
> });
>
> How can I pass slider values ui.values[0] and ui.values[1] to a
> different javascript function which then via AJAX passes the is to the
> ASP script. I tried calling the function like this but it does not
> work:
>
> slide: function(event, ui) {
> $("#amount").val('' +
> (Math.round(Math.pow(10,(ui.values[0] /
> 10))) ) + ' - ' + (Math.round(Math.pow(10,(ui.values[1] / 10))) ));
>
> function myAjax(ui.values[0], ui.values[0]);
> }
> });
> The slieder stops working when I include the function call. What am I
> doing wrong? Please help.
>
>
