var FullImageLocation = img.src.replace('_t.', '.');
On Mar 6, 11:34 am, whoisonfirst <bp.ly...@gmail.com> wrote:
> I have an image url --- it is enclosed in a href.
>
> "images/flavor/websites/oranges_id_t.jpg" title="oranges"
>
> How do I get the url MINUS the _t
>
> so it ends up being "images/flavor/websites/oranges_id.jpg" title="oranges"
>
> that I can pass to a variable of this ?
>
> --
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> context:http://www.nabble.com/Subtract-part-of-url-to-pass-new-url-to-variabl...
> Sent from the jQuery General Discussion mailing list archive at Nabble.com.
