You can just make "perform the action" a separate function and then
call it from the two events
function performAction(){
//do stuff
}
$("#text_input").keyup(function(e)
{
// Checks if the Enter key was entered
if(e.keyCode == 13)
{
performAction();
}
});
$("#push_button").click(performAction);
On Mar 3, 5:40 pm, James <james.gp....@gmail.com> wrote:
> Something like:
>
> $(document).ready(function()
> {
> $("#text_input").keyup(function(e)
> {
> checkKey(e);
> });
>
> });
>
> function checkKey(e) {
> // Checks if the Enter key was entered
> if(e.keyCode == 13)
> {
> // perform the action
> }
>
> };
>
> On Mar 3, 9:26 am, Thierry <lamthie...@gmail.com> wrote:
>
> > I have the following piece of code which checks if a user has pressed
> > the Enter key in a text input with id="text_input" and then performs
> > some action:
>
> > $(document).ready(function()
> > {
> > $("#text_input").keyup(function(e)
> > {
> > // Checks if the Enter key was entered
> > if(e.keyCode == 13)
> > {
> > // perform the action
> > }
> > });
>
> > });
>
> > I also have a button with id="push_button" that I wish will perform
> > the same action as above when clicked. How can I rewrite the above so
> > that I check for either of those two events and perform that one
> > action without code duplication?
