usually you should use $.getJSON when you need jsonp to get data from
another domain
On 3月3日, 上午8时17分, craigpierce <craigpie...@gmail.com> wrote:
> Hi All -
>
> I'm fairly new to jQuery, and totally new to jsonp. I would like to
> see an example of an $.ajax call using jsonp - as of right now, this
> is what I have tried (based on examples found via Google searches and
> the text description on the $.ajax page), but nothing fires any of the
> callbacks:
>
> One:
> function test(){
> var jsonObj ={
> dataOne: "foo",
> dataTwo: "foo",
> };
>
> $.ajax({
> type: "GET",
> url: "https:myurl.com",
> dataType: "jsonp",
> data: jsonObj,
> error: function(){alert('bad');},
> success: function(){alert('good');},
> complete: function(){alert('foo');}
> });
>
> }
>
> Two:
> function test(){
> var jsonObj ={
> dataOne: "foo",
> dataTwo: "foo",
> };
>
> $.ajax({
> type: "GET",
> url: "https:myurl.com",
> dataType: "jsonp",
> jsonp: "testCallback",
> data: jsonObj
> });
>
> }
>
> function testCallback(){alert('foo');}
>
> Three:
> function test(){
> var jsonObj ={
> dataOne: "foo",
> dataTwo: "foo",
> };
>
> $.ajax({
> type: "GET",
> url: "https:myurl.com?testCallback=?",
> dataType: "jsonp",
> data: jsonObj
> });
>
> }
>
> function testCallback(){alert('foo');}
>
> Four:
> function test(){
> var jsonObj ={
> dataOne: "foo",
> dataTwo: "foo",
> };
>
> $.ajax({
> type: "GET",
> url: "https:myurl.com?callback=testCallback",
> dataType: "jsonp",
> data: jsonObj
> });
>
> }
>
> function testCallback(){alert('foo');}
>
> Any help would be much appreciated! Thanks!!!
