On Mon, Mar 2, 2009 at 10:52 AM, Matt Quackenbush <quackfu...@gmail.com>wrote:
> Yes.
>
>
>
> On Mon, Mar 2, 2009 at 3:35 AM, Alain Roger wrote:
>
>> Hi Wil,
>>
>> so if i understood well, having the following JSON:
>>
>>> {"records":[{"id":1,"abbreviation":"fre","description":"french"},{"id":2,"abbreviation":"eng","description"
>>> :"english"},{"id":3,"abbreviation":"ger","description":"german"},{"id":4,"abbreviation":"svk","description"
>>>
>>>
>>> :"slovak"},{"id":5,"abbreviation":"spa","description":"spanish"},{"id":6,"abbreviation":"usa","description"
>>> :"american"},{"id":7,"abbreviation":"ita","description":"italian"},{"id":8,"abbreviation":"por","description"
>>>
>>>
>>> :"portuguese"},{"id":9,"abbreviation":"cze","description":"czech"},{"id":10,"abbreviation":"rus","description"
>>> :"russian"},null,null,null]}
>>>
>>> i should write :
>> $.each(data.records, function(i,item){...});
>>
>> where "data.records" is the name of my JSON result...so records (in my
>> JSON).
>> am I right ?
>>
>
thanks Matt.
