[jQuery] Re: radio buttons and php

[David Muir]

Don't get what you're trying to do either.  jQuery is run client-side, 
php, server-side, so there shouldn't be any php tags showing up in the 
final output. If it is coming through unprocessed, then you've got your 
webserver configured wrong, or your serving php as html.

David

James wrote:
I don't understand what you're doing. What is the PHP "some code"
suppose to be?

On Feb 25, 1:32 pm, lukas <animod...@gmail.com> wrote:
  
I don't get this to work. Somehow the PHP code is ignored within the
radio input forms. Can I change PHP variables within the code and work
with them in the according #div? Does anybody have a hint? Thank you!

jQuery:

        $("#input-l:input:radio,#input-c:input:radio").click(function(){

          if ($(this).is(":checked")) {
             $("#div").show();
           }
         else if($(this).not(":checked")) {
            $("#div").hide();
           }
        });

radio buttons:

<input type="radio" id="input-c" name="user-type" value="1" <?php some
code ?>>
<input type="radio" id="input-l" name="user-type" value="2" <?php some
code ?>>