Also, $($finalurl) likely won't select anything because you're only
passing the classname. It needs to be in the form '.classname'
(prepended by a dot). Try $('.'+$finalurl)
On Wed, Feb 25, 2009 at 2:38 PM, Stephan Veigl <stephan.ve...@gmail.com> wrote:
>
> Hi,
>
> instead of doing a complicate string handling you could simply use
> window.location.hash:
>
> $finalurl = window.location.hash;
>
> For debugging I would do it step by step and not all in one line:
>
> var el = $($finalurl+" :first");
> var src = el.attr("src");
> var src_split = src.split(".");
> var new_src = src_split.join("_on.");
> el.attr("src", new_src);
>
> This way you can use firebug to step through your code and see which
> statement produces the error.
>
> by(e)
> Stephan
>
>
> 2009/2/25 digital <michael.digital.b...@googlemail.com>:
>>
>> Hi, pulling my hair out here.
>>
>> When the page loads I'm collecting a variable from the url which
>> corresponds to the class of an image. I want to then change the image
>> source. I'm doing this because the page doesn't reload and the menu
>> needs to respond to the content if you get my meaning.
>>
>> $url = location.href;
>> $hashtag = $url.search(/#/)
>> $url2 = $url.split("#", $hashtag);
>> $finalurl = $url2[1];
>>
>> This is the code I use to get the class name. When I try to add
>> $finalurl to the attr (see below) it throws an error (undefined,
>> console.log shows it is defined within the if statement).
>>
>> $($finalurl).attr("src", $($finalurl).attr("src").split(".").join
>> ("_on."));
>>
>> Full code:
>>
>> $url = location.href;
>> $hashtag = $url.search(/#/)
>> $url2 = $url.split("#", $hashtag);
>> $finalurl = $url2[1];
>>
>> counttemp = 0;
>>
>> if (counttemp == 0) {
>> console.log($finalurl);
>> $($finalurl).attr("src", $($finalurl).attr("src").split(".").join
>> ("_on."));
>> counttemp = countemp + 1;
>> }
>>
>> Any help would be greatly appreciated.
>>
>
