Try this: "5"-2 == 3;
If you need to increment you can't just use a '+' to convert the
string, or parseInt/Number as everyone already pointed out.
shapper:
$index = $('#Index');
$index.val( +$index.val()+1 );
cheers,
- ricardo
On Feb 11, 4:47 pm, brian <bally.z...@gmail.com> wrote:
> On Wed, Feb 11, 2009 at 1:23 PM, Ricardo Tomasi <ricardob...@gmail.com> wrote:
>
> > Increment/decrement is for variables. You can't use it directly on a
> > number. Try '3--'.
>
> > Make it simple, if you use subtraction the type conversion is done for
> > you:
>
> > $index = $('#Index');
> > val = $index.val()-1;
>
> Except, as Karl pointed out, val() will return a string.
>
> var val = parseInt($index.val());
> $index.val(--val);
