"But this does NOT
$("div.image")[4]."
Because that is not a jQuery object
On Jan 25, 4:52 pm, donb <falconwatc...@comcast.net> wrote:
> Try
>
> $("div.image").eq(4).show()
>
> I would only be guessing, but $("div.image")[4] must gets you
> something that's not an object possessing a show() method.
>
> On Jan 25, 4:41 pm, bartee <bar...@gmail.com> wrote:
>
> > bump..
>
> > Anyone have any ideas why this does not work.. ????
>
> > On Jan 25, 11:01 am, bartee <bar...@gmail.com> wrote:
>
> > > This works...
>
> > > $("div.image").slice(4,5).show()
>
> > > But this does NOT
>
> > > $("div.image")[4].show()
>
> > > Seems like the [4] should work !!
