Do you have to start with two jQuery objects? It would be a lot easier
if you could start with two simple selectors. For example, given
div.outer and span.inner, to see if span.inner is a descendant of
div.outer, you could go from the other direction:
$('div.outer:has(span.inner)').length
If you realy need it to be a child, and not any descendant, you could do
$('div.outer:has(> span.inner)').length
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Jan 22, 2009, at 4:39 AM, Richard D. Worth wrote:
My first thought was to try these and neither worked
$(b, a).length
a.find(b).length
Also, no luck here
$(b[0], a[0]).length
a.find(b[0]).length
In the end this is the one I could get to work
$(b).parents().filter(function() { return this === a[0]; }).length
- Richard
On Thu, Jan 22, 2009 at 4:25 AM, James Hughes <j.hug...@kainos.com>
wrote:
Hi,
This is probably a really easy question an I apologise if it appear
stupid but I am clueless right now. Given 2 jQuery objects (a,b)
how can I tell if b is a child of a?
James
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