*type: $jQ("#country_id").val(my_value);
-------------
Read jQuery HowTo Resource - http://jquery-howto.blogspot.com
On Wed, Jan 14, 2009 at 4:24 PM, Beres Botond <boton...@gmail.com> wrote:
>
>
> It seems you don't know what .select() should be used for. It has
> absolutely nothing to do with selecting and option of a select box.
> Read the docs carefully.
> http://docs.jquery.com/Events/select
>
> Try this instead (assuming that #country_id is a select box):
>
> $jQ("#country_id]").value(my_value)
>
>
> ocptime wrote:
>> Hello There,
>>
>> I want to dynamically add a select option to an existing select
>> dropdown when a new country is added. This i was able to do using:
>>
>> $jQ("#country_id option[value='new']").before("<option value='" +
>> value + "'>"+ name + "</option>");
>>
>> After that i want to get selected the just now appended country option
>> and must change from the "--New Country--" . For that i used the select
>> () as below:
>>
>> $jQ("#country_id option[value='" + value + "']").select();
>>
>> This seems to be not working.
>>
>> Even if i put a static value this is not changing:
>>
>> $jQ("#country_id option[value='144']").select();
>>
>> Any pointers ?
>>
>> Thanks in Advance,
>>
>> Regards
>> ocptime
