Not sure that this is it, but
$.fn.myplugin = function(options) {
return this.find('form').ajaxForm();
});
?
On Jan 6, 1:59 pm, yellow1912 <yellow1...@gmail.com> wrote:
> Hi all, I have a question regarding jquery object:
>
> if I bind my plugin like this:
>
> $('#myButton').myplugin();
>
> And inside my plugin, I want to bind ajaxForm listener to all forms
> inside 'this' current element, what is the best way to do it? I can
> get the id by using $this.attr('id'), but there is no guarantee that
> the users will always pass in an id.
>
> (function($) {
> //
> // plugin definition
> //
>
> $.fn.myplugin = function(options) {
> // bind ajax form to 'this'
>
> }});
>
> Thank you for your help and suggestions
>
> Raine
