That is an excellent idea; I agree completely. There's nothing inefficient
about it either.
It also leaves the door open to return additional data without breaking your
existing code.
{ "valid":true }
{ "valid":false }
Now if you want to add other properties to that data, you don't have to
change the code that does an "if( json.valid )" test.
-Mike
> From: donb
>
> This is probably a good reason to make it a habit to return a
> JSON object, so that the data is not simply a string of
> characters with the associated ambiguities. I realize this
> leaves me open to counterarguments of 'it's not a efficient'
> but really that's a minor worry (to me that is).
>
> On Jan 2, 5:23 pm, "Michael Geary" <m...@mg.to> wrote:
> > The 'if' statement in JavaScript is reliable.
> >
> > If your "if( data == 'no' )" is taking the "else" path, the most
> > likely reason is that the data variable is indeed not equal to "no".
> >
> > Even though the console.log showed a value of "no", are you
> sure there
> > isn't a newline at the end? What does
> "console.log(data.length)" show?
> >
> > You can also use the Fiddler2 debugging proxy, or the Net tab in
> > Firebug, to see the actual length of the body of the
> response from the PHP script.
> >
> > My suspicion is that there's an extra newline at the end of
> your PHP script.
> > Your PHP script actually looks like this, doesn't it?
> >
> > <?php
> > ...your code...
> > ?>
> >
> > Depending on the version of PHP, a single newline after the
> ?> may not
> > add a newline to the output, but if there are two newlines
> after the
> > ?> you'll definitely get an extra newline in the output - and it
> > wouldn't necessarily be obvious from looking at the PHP
> code in a text editor.
> >
> > Remember that anything before the opening <?php or after
> the closing
> > ?> is rendered directly as part of the HTML output.
> >
> > Because of this, best practice in a pure PHP script is to
> *omit* the
> > closing ?>. The language does not require it, and omitting
> the closing
> > ?> insures that you won't get any spurious newlines in your output.
> >
> > If this isn't it, post a link to a test page that
> demonstrates the problem.
> >
> > -Mike
> >
> > > From: wattsup
> >
> > > I am having some problems with a jquery script that I am writing.
> > > The problem is after I receive the data from the php file jquery
> > > seems to skip the if statement. I am logging to console
> and it is
> > > showing yes/ no depends on email address. I am enclosing
> my scripts
> > > in case someone can help me.
> >
> > > <script src="javascripts/jquery-1.2.6.js" type="text/javascript"
> > > charset="utf-8"></script>
> > > <script src="javascripts/jquery.validate.js"
> type="text/javascript"
> > > charset="utf-8"></script>
> > > <script src="javascripts/jquery.corner.js" type="text/javascript"
> > > charset="utf-8"></script>
> > > <script src="javascripts/jquery.lightbox.packed.js"
> > > type="text/ javascript"></script>
> >
> > > $(document).ready(function(){
> > > $("#email").blur(function(){
> > > var post_string = $(this).val();
> >
> > > $("#msgbox").removeClass().addClass('messagebox').text
> > > ('Checking...').fadeIn(1000);
> > > $.post("php/email.php",{ email_check:
> > > post_string} ,function(data){
> > > console.log(data); // show
> data value in
> > > console
> > > if(data=='no') { // email
> not avaiable
> > > <------------------------- Skipping this area
> >
> > > $("#msgbox").fadeTo(200,0.1,function(){
> >
> > > $(this).html('email address already exists').addClass
> > > ('messageboxerror').fadeTo(900,1)
> > > });
> > > } else { // email avaiable
> > > <-------------------------- Always gos here no matter what
> >
> > > $("#msgbox").fadeTo(200,0.1,function(){
> >
> > > $(this).html('email available to register').addClass
> > > ('messageboxok').fadeTo(900,1);
> > > });
> > > } // end if
> > > }); // end post
> > > }); // end email blur
> > > }); // end doc ready
> >
> > > PHP FILE
> >
> > > if(isset($_POST['email_check'])) {
> > > $email = $_POST['email_check'];
> >
> > > require_once('config.inc.php');
> > > require(MYSQL);
> >
> > > $result = @mysql_query("SELECT * FROM members WHERE
> (user_email =
> > > '$email')");
> > > $row_num = mysql_num_rows($result);
> >
> > > if( $row_num > 0){
> > > // "unavailable to register";
> > > $valid = "no";
> > > }else{
> > > // "available to register";
> > > $valid = "yes";
> > > };
> >
> > > echo $valid;
> > > mysql_close();
> > > }
> >
> > > I have been working on this all day and can not figure
> out why the
> > > data is skipping the if statement. if you have any ideals
> please let
> > > me know.
>
