I tried that, but I get an error in Firebug that Shadowbox was undefined. So, I need to know how to "define" Shadowbox as a function, then issue the command to close it.
I tried: $Shadowbox.close() After the lines below, but that wasn't right...Firebug still tells me that Shadowbox is undefined. $(function)Shadowbox.close() but that didn't work. I just can't find the correct syntax... Rick > -----Original Message----- > From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On Behalf Of brian > Sent: Wednesday, December 10, 2008 6:38 PM > To: jquery-en@googlegroups.com > Subject: [jQuery] Re: How do I write a function to close shadowbox? > > > Shadowbox.close() > > (I've never used it Myself, so YMMV) > > On Wed, Dec 10, 2008 at 4:10 PM, Rick Faircloth > <[EMAIL PROTECTED]> wrote: > > > > For my "success" callback (I guess that's what you call it...) > > I've got a series of events after an $.ajax post. > > > > Here they are: > > > > $('#contentdiv').empty().fadeIn(1000).append(response.login); > > $('#my_story').empty().fadeIn(2000).append(response.my_story); > > $('#email').empty().fadeIn(2000).append(response.email_address); > > $('#pass').empty().fadeIn(2000).append(response.password); > > > > These evens happen inside a shadowbox modal window. > > > > After the last one, I want to auto-close the shadowbox. > > > > The shadowbox command for doing that is .close() . > > > > What I can't figure out is how to reference shadowbox itself > > like I do elements with an id or class, etc. > > > > Anyone got a pointer for this? > > > > Thanks, > > > > Rick > > > >
