You need to simply pass the name of the function without parentheses like so

$("#qSearchBut").click(quickSearch);

Otherwise it executes the function immediately (upon parsing) and passes the
result as an argument to .click().

- Richard

On Fri, Nov 21, 2008 at 9:30 AM, .mini.moke <[EMAIL PROTECTED]>wrote:

>
>
> Hi there,
>
> I'm pretty new to JQuery.  I have a couple of elements that need to call
> the
> same function so my code looks like this:
>
> $("#qSearchBut").click(quickSearch());
>
> Pretty simple I thought.  But this call executes the quickSearch() function
> on page load.  What fundamental thing am I overlooking?
>
> Thanks in advance
>
> Amanda
> --
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> Sent from the jQuery General Discussion mailing list archive at Nabble.com.
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